solve in linear equations 2b over3-3bover2=15?

Question

can some one help me to sollve this equation for me

Answer 1

2b/3 -3b/2 = 15

Multiply by 6

(2/3)6 = 4

(3/2)6 = 9

4b - 9b = 90

Combine like terms

-5b = 90

Divide by -5

b = -18

Answer 2

First, use your math symbols"
2b/3 - 3b/2 = 15
Multiply all terms by 6
4b - 9b = 90
-5b = 90
b = -18

Answer 3

2b/3 -3b/2 = 15

First get a common denominator. For 2 and 3, the LCD is 6.

4b/6 - 9b/6 = 15

-5b/6 = 15

-5b/6 * 6 = 15 * 6
-5b = 90
b = 90/-5
b = -18

Answer 4

2b/3 - 3b/2 = 15
4b/6 - 9b/6 = 15 (get a common denominator)
4b - 9b = 90 (multiply through by the denominator)
-5b = 90 (combine terms)
b = -18 (divide both sides by -5)

Answer 5

you may the two use substitution or removal. Substitution: a million)resolve one equation for y so as which you have basically one variable to unravel for: y=2-7x 2) Now, understanding what y equals, plug the fee in to the subsequent equation so as which you have 5x+2(2-7x)=4 3) Now resolve for x. the respond is x=0 4) Now plug x back into the 1st equation to locate y. the respond is y=2 5) Now plug in the two your values to the two your equations to verify if the values are perfect suited. _____________________________________ removal: a million) Multiply the full first equation by potential of -2 so as which you will cancel out the y's. this delivers: -14x-2y=-4 5x+2y=4 2) Now cancel out the y's by potential of including the two equations. This leaves you with: -11x=0 3) resolve for x and locate that x=0 4) Plug your x fee into one equation to locate the fee of y. 5) 7(0)+y=2, so y=2 6) Plug on your 2 variables x=0 and y=2 into the two equations to ascertain that your values are perfect suited.

Answer 6

2b/3 - 3b/2 = 15
4b - 9b = 90
- 5 b = 90
b = - 18

Answer 7

b=-18

Answer 8

2b/(3-3b)/2 = 15

can also be written as

2b * 2/(3-3b) = 15

4b/(3-3b) = 15

cross multiply,

4b = 45 - 45b

49b = 45

b = 45/49