Hello i need some help with this alg?

Question

okay it tells me 2 simplify 6+4^2/2-1 i put it in the calculator and it gives me a long number with decimals is ther another way yo simplify expressin thnx

Answer 1

The question has to be clearly expressed.
Assume that it is:-
(6 + 4²) / (2 - 1) = (6 + 16) / 1 = 22

However it may be that you mean:-
6 + 4²/2 - 1 = 6 + 16/2 - 1 = 6 + 8 - 1 = 13

You choose!

Answer 2

6+4^2/2-1 = 6 + (4^2)/2 -1

= 6 + (16)/2 - 1

= 6 + 8 -1

= 13

Answer 3

you need to put in parentheses to show how the terms are grouped. the way you 've written it,

6+4^2/2-1 = 6 + 16/2 - 1 = 13 but

6+4^2/(2-1) = 6 + 16/1 = 14 however

[(6+4)^2/2]-1 = [100 / 2 ] - 1 = 49

and there are other combinations -- even some that might give you a long number with decimals

Understanding the problem is the first step to solving it.

Answer 4

6+4^2/2 - 1
6 + 4^(2/2-1)
6+ 4(1-1)
6+ 4^0
6+1= 7
anything to the power of 0 is 1
and any number divided by itself 1

Answer 5

6 + 16 / 2 -1?
22/1 = 22

Answer 6

Hi,

For this question, 4^(2/2) is like saying 4 since 2/2 is just 1. Therefore, your problem comes out to be:

6 + 4 - 1 <--- (NOTE: You really don't need parentheses like other people say. You can just say 6+4+-1 since adding a negative number is like subtracting a positive)

Therefore: 6 + 4 + -1 which is equal to 9.

I hope that helps! Please let me know if you have any other questions!

Sincerely,

Andrew

Answer 7

some ( ) would help
I think this is 6+4^(2/2)-1=6+4-1=9
it could be 6+ (4^2)/2-1=6+16/2-1=6+8-1=13

Answer 8

6+16/2-1
6+8-1
13