For the equation x-^x =0, perform the following. Solve for all values of x that satisfies the equation.?

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For the equation x-^x =0, perform the following. Solve for all values of x that satisfies the equation.?

2007-05-19 14:13:09 · 4 answers · asked by ladymiriam@sbcglobal.net 1 in Science & Mathematics ➔ Mathematics

4 answers

There is something wrong in the equation... -^ has no meaning in Math.

If the equation is x^x = 0, then there is no solution...

Note: 0^0 is not a number, then x cannot be zero.

2007-05-19 14:21:52 · answer #1 · answered by vahucel 6 · 0⤊ 0⤋

If this is an exponential function there is no solution as x raised to any real number only exists if x>0

2007-05-20 03:25:21 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋

x= Huh?
the other x+ a huge headache

2007-05-19 14:21:00 · answer #3 · answered by Coco 2 · 1⤊ 0⤋

Do you mean x^-x (x to the negative x power?)

2007-05-19 14:20:56 · answer #4 · answered by Anonymous · 1⤊ 0⤋