2007-05-19 11:39:39 · 5 answers · asked by betty 2 in Science & Mathematics ➔ Mathematics
Consecutive angles in parallelograms are supplementary. If you throw on a temporary placeholder of x to your ratio numbers, you can call the two angles 3x and 7x. Since supplements,
3x + 7x = 180
10x = 180
x = 18 --> 3*18 = 54° and 7*18 = 126°
2007-05-19 11:47:58 · answer #1 · answered by Kathleen K 7 · 0⤊ 1⤋
A/B = 3/7
solve for B.. to get
B= 7/3 A
now, since they are consecuitive, they are suplementary
i.e. A +7/3 A = 180
or, A= 54
and B is 7*54 /3
B = 126
2007-05-19 11:48:06 · answer #2 · answered by JAC 3 · 0⤊ 0⤋
assume the angles are X and Y, such that X/Y = 5/4, i.e. Y = 4X/5 additionally, all of us understand that X+Y = one hundred eighty ranges consequently, X + 4X/5 = one hundred eighty 5X/5 + 4X/5 = one hundred eighty 9X/5 = one hundred eighty 9X = 5 * one hundred eighty = 900 X = 900/9 = a hundred Y = one hundred eighty - a hundred = 80 So the angles are 80 and a hundred. 80 is acute (decrease than ninety) and a hundred is obtuse (between ninety and one hundred eighty). consequently the respond is #3.
2016-11-25 01:30:59 · answer #3 · answered by ? 4 · 0⤊ 0⤋
3x+7x = 180
x= 18
3x = 54 degrees
7x = 126 degrees
2007-05-19 11:46:20 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋
consecutive angles are supplementary, so the angles are c & 180º-c
3*c=7*(180º-c)
3c=1260º-7c add 7c to each side
10c=1260º
c=126º
d=180º-126º
d=54º
the angles are 54º & 126º
2007-05-19 11:44:11 · answer #5 · answered by yupchagee 7 · 0⤊ 1⤋