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3 answers

x – 2y < 4 --> x-4<2y --> y > x/2-2 <--Inequality 1
x<4 <-- Inequality 2

Plot the points (4,0) and (0,-2). Draw a dashed line through these two points and this line is Inequality 1.

Now draw a vertical dashed line through (4,0). This is inequality 2

Now the solution is all points that lie above the inequaliiyt 1 lie AND to the left of th Inequality 2 line.

2007-05-19 09:21:19 · answer #1 · answered by ironduke8159 7 · 0 0

draw the the two straight lines X=4 and x-2y=4

x<4 is the area on the left of line x=4

x-2y<4 is the are over line x-2y=4

the common area is the solution you are looking for

2007-05-19 16:17:27 · answer #2 · answered by zio bebo 2 · 0 0

x - 2y = 4 has x-intercept at 4, y-intercept at -2. Draw a dotted line through those points (solid if ≤), and lightly shade the left (x is less) side of the line. for x = 4, draw a dotted VERTICAL line through 4 on the x-axis, and lightly shade the left (x is less) side. Where you've shaded twice, shade darker. That's your solution set.

2007-05-19 16:13:42 · answer #3 · answered by Philo 7 · 0 0

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