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Soory , guys , I am on TCP/IP lessons , hard to decide this , personally I thinks yes .

Hey , but If in your school , univer , you have assignments , works practice documents abt this subject that are online , please share me ! 'cos I have little practice and scenario to think ..
You know , more practice , better ..

2007-05-19 08:09:50 · 11 answers · asked by andrew martin 1 in Computers & Internet Computer Networking

11 answers

No, it wouldn't.

It's easier if you look at it as simple math. To tell wether two computers can talk to each other, the PC's do a simple math calculation on the IP addy and subnet mask of both. It does a calculation between the IP and SNM of PC#1, then another between the IP and SNM of PC#2. If the two calculations return the same result, then they are on the same subnet and can talk.

PC1:
192.168.10.1
255.255.255.0 (logical AND)
--------------------
192.168.10.0 (result)

PC2:
192.168.10.2
255.255.0.0
------------------
192.168.0.0 (Result)

As you can see, the results of the two calculations don't match, they are on different subnets and cannot talk. If they were both /16 or both /24, that would be different.

2007-05-20 02:20:28 · answer #1 · answered by The Psycho 6 · 0 0

NOOO!!! They are not on the same subnets, yet as long as there is a router between the two of them they can still communicate with each other.

the "/24" identifies the subnet for the first network address to be the first 3 octets of the address- 192.168.10.0 (24/8=3) and the last octet to be the host. While in the second network address the subnet is the first 2 octets- 192.168.0.0 (16/8=2). So the first IP address is under the 192.168.10.0 while the second IP address is under 192.168.0.0.

P.S. Dragonfire needs to study a little more so he can realize that the "/24" and "/16" aren't literally a part of the IP address. They are merely a simpler way of writing the subnet mask (instead of writing 1111.1111.1111.0 and 1111.1111.0.0)

2007-05-19 09:37:58 · answer #2 · answered by Freebrum 3 · 0 0

192.168.10.1/24. 200.100.100.100/32. NewYork. NYDMZSRV. 192.168.10.11/24 ... Make sure the host on the NY LAN is receiving a dynamic IP Address ...
IP address 192.168.10.1 is listed here as rfc1918 misc.

RFC1918 addresses are not globally unique. They are reserved for internal use in private networks. There is no point in asking any sort of ip address based public reputation system about the spam reputation of such an address. Such dns queries are simply extra noise.
How to Troubleshoot Black Hole Router Issues see link 1 below:
Setting up a home network link 2
10-step total networking
You can get a complete home network up and running in 10 easy steps. Here's a summary of what's involved:

Take stock of your existing hardware.

If you wish to share an Internet connection using Internet Connection Sharing (ICS), choose which computer will be your ICS host.

Decide what type of network technology you wish to use.

Make a list of the hardware you need for each computer.

Install the network adaptors and install your modem on the ICS host computer.

Physically cable the computers together.

Switch on all computers, printers and other peripherals.

Make sure the ICS host is connected to the Internet.

Run the Network Setup Wizard on the ICS host.

Run the Network Setup Wizard on the other computers on the network.
And for subnet mask CHEAT SHEET? See link 3 below
Cheers

2007-05-19 08:33:36 · answer #3 · answered by The Thinker 6 · 0 1

Yes they will. They are both in the same subnet anyway. And to those who think 1/24 should be 124, you need to study as well!

2007-05-19 08:25:10 · answer #4 · answered by Anonymous · 2 0

If they are on the same subnet, yes, as long as the first 3 set of numbers are identical and on the same subnet you will always beable to talk. Providing the are physically connected that is......

2007-05-19 08:40:11 · answer #5 · answered by Taba 7 · 0 0

The address 192.168.10.1/24 and 192.168.2/16 make use of wildcard masks, and from what I could gather they are used in setting up access lists. This might help you understand a little more about them, and if they can communicate.

http://www.rhyshaden.com/ipadd.htm

2007-05-19 11:07:49 · answer #6 · answered by Mike W 7 · 0 0

since the Network id for these two are different
that is 1st 24 bit for 192.168.10.1
and 1st 16 bit for second one.
so these belong to 2 different network.
so they cannot communivate directly rather
u need a router in between for communication.

2007-05-19 10:16:07 · answer #7 · answered by Hero 2 · 0 0

124 you mean and not 1/24.. and 216 and no 2/16 right? as neither address with a / are valid IP address
and yes you can communicate since they are on the same subnet

2007-05-19 08:13:16 · answer #8 · answered by Anonymous · 0 4

No they won't connect bcoz they are in different network the default mask for /24 is 255.255.255.0 and for/16 is 255.255.0.0

2007-05-19 18:39:09 · answer #9 · answered by pattu 1 · 0 0

of course yes

2007-05-19 08:11:54 · answer #10 · answered by Anonymous · 0 1

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