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24h/32h^6 divided by 60h^6/24h^4
a) 3/10h^7
b) 2/h^3
c) 10h^6/3

2: e/e^3 divided by -5r^2 - 15r
a) r+3/e^2
b) 3/r-3
c) e^2/r+3

3:
e^6 - 3e^4/27 divided by e^4/6e + 24
a) (2e^2 + 6)(e - 3)/9
b) 2(e^2 - 3)(e + 4) /9
c) 2e^3 + 8e^2 + 6e - 24 /9e

4:
-3r/-7d divided by -12r^2/-21d^2
a) 3d/4r
b) 4r/5d
c) 5d/4r

2007-05-19 06:51:24 · 2 answers · asked by Morgan 1 in Science & Mathematics Mathematics

2 answers

1. 24h/32h^6 divided by 60h^6/24h^4
24h/32h^6 * 24h^4/60 h^6=
4/4h^2* 3/10h^5 12/40h^7= 3/10h^7

2.e/e^3 divided by -5r^2-15r
e/e^3 divided by -5r(r+3)
1/e^2 divided by -5r(r+3)
-5r(r+3) * 1/e^2= -5r(r+3)/ e^2

3. e^6-3e^4/27divided by e^4/ 6e+24
e^4(e^2-3)/27 multiply 6(e+4)/e^4
the 6 becomes 2 and 27 becomes 9 and e^4 cancel out

e^2-3/9 * 2(e+4)
2(e^2-3)(e+4)/ 9

4.-3r/-7d divided by -12r^2/-21d^2

-3r/-7d * -21d^2/-12r^2
-3rbecomes 1 -12r^2 becomes 4r
-7d becomes 1 -21d^2 becomes 3d
3d/4r

2007-05-19 07:45:54 · answer #1 · answered by Dave aka Spider Monkey 7 · 0 0

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2007-05-19 13:55:52 · answer #2 · answered by GURUBHAI 1 · 0 0

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