(y^7/z^6)^3
=y^21/z^18
2007-05-19 05:50:23
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answer #1
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answered by ironduke8159 7
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(y^7)^3/(z^6)^3
=y^21/z^18
2007-05-19 06:37:28
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answer #2
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answered by arnab b 2
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its easy, you will only multiply the exponents, you don't have to divide y^7 to z^6 because they don't have the similar variable so its impossible.....
anyway the answer is y^21/z^18
2007-05-19 06:42:10
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answer #3
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answered by Anonymous
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2016-12-11 14:06:05
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answer #4
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answered by Anonymous
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y^21 / z^18 or y^21.z^(- 18)
2007-05-19 10:54:27
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answer #5
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answered by Como 7
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(y^7/z^6)^3 = y^21/z^18
explanation:
(a^m)^n = a^(m*n) thus
(a^m/b^k)^n = a^mn/b^kn
2007-05-19 05:55:38
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answer #6
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answered by mahou kurisutaru 2
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