2007-05-19 04:32:03 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
SImple
Using a large graduated cylinder or other grauated volume device (a measuring cup) - fill it up to some height that is taller than your kg of pure gold. Than, drop the gold in the water and record the new volume. SUbtract the initial volume (the water) and shazzam! You have the volume of your kg of gold.
Water displacement for the win!
This is implying you do not have the density of your gold kilogram. The density could vary after all. If you know the mass, then you can use the density equation
Density = mass/volume so Voume = mass/density. Using the density for pure gold (19.3 * 10^-3) you can get the volume. However, of you do not know the mass, water displacement is the chemists way to go (seriously).
2007-05-19 04:38:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The Density of pure gold = 19.3 g/cc)
Mass/Volume = Density
Volume = Mass/Density = 1000 ÷ 19.3 = 51.8 cc
2007-05-22 14:10:58 · answer #2 · answered by Norrie 7 · 0⤊ 0⤋
rho = M/V; where rho is gold mass density, M is the mass = 1 kg, and V = the volume. Look up rho in any chemistry book and simply solve for V = M/rho. (Note...make sure rho's units are in SI kg-m-sec units as appropriate for mass density.)
2007-05-19 11:45:30 · answer #3 · answered by oldprof 7 · 0⤊ 0⤋
mass/density so
1kg/
19.3e-3 kg·cmâ3
so 1/(19.3e-3) = 51.8134715
so 51.8134715 cm^3
2007-05-19 11:36:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Where is it...lemmme see it...
2007-05-19 12:51:59 · answer #5 · answered by Anonymous · 0⤊ 0⤋