I no a product is iodine... what about the half equations, then full equation?
2007-05-19 00:53:58 · 4 answers · asked by Anthea G 1 in Science & Mathematics ➔ Chemistry
The iodide ion is oxidised to iodine, but there are three very distinctive reduction products of the H2SO4 that make this a very, very messy reaction (but they love setting it in exams!). SO2, S and H2S are all formed, and each one has a different half equation for you to work out.
In addition to all this, of course, is the acid-base reaction that liberates white fumes of HI.
2007-05-19 01:27:21 · answer #1 · answered by Gervald F 7 · 0⤊ 1⤋
Diet Coke
2007-05-19 00:57:45 · answer #2 · answered by ELofty 2 · 1⤊ 2⤋
H2SO4 +2 KI >> K2SO4 + 2HI
2007-05-19 00:57:33 · answer #3 · answered by Anonymous · 0⤊ 1⤋
first answer is correct...But alternatively...KI + H2SO4 --> K2SO3 + H2O + I2
2007-05-19 01:05:18 · answer #4 · answered by Michael John J 3 · 1⤊ 1⤋