2007-05-17 22:41:11 · 5 answers · asked by vanisha j 1 in Science & Mathematics ➔ Mathematics
let x = sin^(-1)(15 / 17)
cos x = a / 17
17² = a² + 15²
a² = 17² - 15²
a² = (17 - 15).(17 + 15)
a² = 64
a = 8
cos x = 8 / 17
2007-05-17 23:09:37 · answer #1 · answered by Como 7 · 0⤊ 0⤋
x = (sin^-1)(15/17)
sin x= 15/17
sin^2 x + cos^2 x = 1
cos^2 x = 1 - 15^2/17^2
=(289-225)/289
=64/289
cos x = sqrt(64/289)
= 8/17
2007-05-17 22:47:36 · answer #2 · answered by gudspeling 7 · 0⤊ 0⤋
Let theta = sin-inverse 15/17
so sin theta is 15/17
but we need cos theta
using formula cos theta = sqrt ( 1 - sin^2 theta)
we get cos theta = 8/17
2007-05-17 22:49:53 · answer #3 · answered by ? 3 · 0⤊ 0⤋
17^2 - 15^2 = 64
cos((sin^-1)15/17) = 8/17
2007-05-17 22:45:41 · answer #4 · answered by Helmut 7 · 0⤊ 1⤋
15/17= .882352941
arcsin.882352941=61.92751304
cos61.92751304=0.470588236
2007-05-17 22:49:38 · answer #5 · answered by Anonymous · 0⤊ 0⤋