solve 2x^2+5x+3=0?

Answer 1

Simple & easy

Answer: x = - 1 or - 1.5

STEPS:

2x ^2 - 5 x + 3 = 0 ... ( given equation)

This can be written as

2 x ^2 + 2x + 3x +3 = 0

Taking the common factor out,

we get 2x ( x+1) + 3 ( x + 1)

=> (2x + 3) (x + 1) = 0

case 1: either (2x + 3) must be = 3;

then x = (3/2) or 1.5... (answer 1)

Case 2: (x + 1) must be = 0

Then, x = - 1.... Answer (2)

ANSWER: x = - 1 0r - 1.5

Answer 2

With What form of equation

Quadratic
(-b+-SqrRoot(b^2-4(a)(c))/2(a)
A=2
B=5
C=3
Just plug in

Sum And Product
2x^2+5x+3=0 S=5 P=6
Sum= Middle Number
Product= Outside Numbers 2x multiplied by 3
Common Numbers (2,3)
Sub 2 and 3 in place of 5
2x^2+2x+3x+3
Remove Common Numbers
2x(x+1)3(x+1)
(x+1)(2x+3)
X=-1| 2x=-3 x=3/2 X=-1.5
(-1,-1.5)

Answer 3

2x^2+5x+3=0
(2x+3)(x+1)=0

x = -3/2
x = -1

Answer 4

2x^2+5x+3 = sqrt(2) (sqrt(2) x^2 + sqrt(2)5/2 x + 7 - 4 = 0

Answer 5

2x^2+5x+3=0
2x^2 + 2x + 3x + 3 = 0
2x(x+1)+3(x+1)=0
(x+1)(2x+3)=0
x+1=0 --> x = -1
2x+3=0 ---> x = -1.5

x=(-1.5,-1)

Answer 6

factor
(2x +3)(x + 1) = 0
2x + 3 = 0
2x = -3
x = -3/2

x+1 = 0
x = -1

Answer 7

(2x+3 )(x +1) = 0
x = -3/2 and x = -1

Answer 8

Did you hassle to be taught your consequences? is two(-3)^2 + 5(-3) - 3 equivalent to 0? is two(a million/2)^2 + 5(a million/2) - 3 equivalent to 0? I verify my consequences each and every time, each and every time! i'm solid at this "stuff" yet no longer appropriate. Are you appropriate? i assume no longer because of the fact which you're "very perplexed."

Answer 9

(2x+3)(x+1)
x= -3/2 or x = -1
or by the other method
-5 + or - 7
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4

Answer 10

(2x+3)(x+1)+0

x = -3/2

x = -1