solve the following system of equations?

Question

x+y=6 and then at the bottom will be
x-y= -2

Answer 1

x+y=6
x-y= -2

Add top and bottom
2x = 4
x = 2
Now put x = 2 into top
2 + y = 6
y = 6-2 = 4

Answer 2

x+y=6 -----(1)
x-y=-2..........(2)
Add equation 1 and 2
(x+y)+(x-y)=6 +(-2)-
x+y+x-y =6-2
2x =4
therefore x=4/2=2
place the value of x in equation 1
2+y=6
y=6-2=4

Answer 3

okay, you're trying to make 1 variable disappear, to do that, you have to add or subtract one of the variables, sometimes like the problem above, you can do that right away, so i'll solve
x+y=6
+x-y=-2 You see how by adding a y+-y equals 0, that's how you make it disappear. now remeber to watch your signs, and remember to add your whole equation.
you'll get 2x=4 x=2, now plug it in to the orgional question(1 of the 2 would work)
2+y=6 subtract and you'll get y=4
now, if you have 2x+2y =6, 3x+y=6, you'll have to multiply by the LCM to do what's shown above.

Answer 4

You add them together.
2x=4
x=2
Plug it back to one of the equations.
2+y=6
y=4

Answer 5

Add:-
2x = 4
x = 2
y = 4

Answer 6

Easiest way is elimination generally.
x+y=6
x-y=-2
Add together...
2x=4
x=2
Then go back
(2)+y=6
y=4

Fun stuff.

Answer 7

x+y=6

x = 6 - y <-----------eq 1
x-y= -2 <--------------eq 2
add eq 1 into eq 2

x-y= -2 <--------------eq 2
6 - y -y = -2
6 -2y = -2
2y=8
y=4