solve the following system of equations?

Question

x=3y+7 and then at the bottom will be
x=2y-1 can u guys explain me how to do the step by step

Answer 1

x=3y+7
x=2y-1
Take top - bottom
0 = y + 8
y = -8
Now put into second equation
x = 2(-8) -1 = -17

Answer 2

If there's a quadratic, then there'll maximum in all hazard be 2 solutions. first of all, the addition approach would artwork completely in this technique. upload the main appropriate components and the left components to get. y + 5x + 6x^2 - 13x - y = 3 - 5 be conscious how the 'y's cancel out 6x^2 - 8x = -2 Divide the two components by technique of two 3x^2 - 4x = -a million 3x^2 - 4x + a million = 0 (3x - a million)(x-a million) = 0 x = a million ; a million/3 Now plug it into the less annoying equation to remedy for y y + 5x = 3 y = 3 - 5x y = 3 - 5(a million) y = 3 - 5(a million/3) y = -2 ; 4/3 so the recommendations are ( a million , -2 ) , ( a million/3 , 4/3)

Answer 3

First, substitue 2y-1 in for the x on the top equation. Next, solve for y. Once you solve for y which is -8, then you plug in -8 for the y in the top equation and solve for x which -17. If you want to check your answer take one of the equations plug -17 where the x is and -8 where the y is and your answer should be -17=-17 which indicates that x=-17 and y=-8.

Answer 4

3y + 7 = 2y - 1
y = - 8
x = -16 - 1
x = - 17

x = - 17 , y = - 8

Answer 5

3y+7=2y-1
y+7=-1
y= -8
x=3y+7
x=3(-8)+7
x= -17
(-17,-8)