If299 is divisible by 2b and b represents a positive digit , what is the value of b?

Answer 1

First, we see that b must be odd.
Also, it cannot be 5 since 299 doesn't end in 5.
It can't be 7 or 1 because 27 and 21
are both divisible by 3 and
299 isn't. Also it can't be 9 because 299 = 9(mod 29).
That leaves only 3 for b, and 3 works:
299 = 23*13.
The answer is: The value of b is 3.

Answer 2

b=13

Answer 3

let 299/2b=k,where k is any real number.therefore b=149.5/k.
but k as well as b can never be 0.