A fourth of july rocketis moving at a speed of 50 m/s. the rocket suddenly breaks into 2 pieces of equel mass?

Question

and they fly off with the velocities v1 and v2, as shown in the drawing. what are the magnitudes of v1 and v2?

pic:
http://img502.imageshack.us/img502/821/untitledzl7.png

Answer 1

m1v1sin30° = m2v2sin60°
50(m1 + m2) = m1v1cos30° + m2v2cos60°
but m1 = m2, so
v1sin30° = v2sin60°
50(2) = v1cos30° + v2cos60°
v1 = v2sin60°/sin30°
100 = v2(sin60°cos30°/sin30° + cos60°)
100 = v2((1/2)√3(1/2)√3/(1/2) + 1/2)
100 = v2((1/2)3 + 1/2)
200 = v2(3 + 1)
|v2| = 50 m/s
|v1| = 50(1/2)√3/(1/2)
|v1| = 50√3
|v1| ≈ 86.6 m/s

Answer 2

possibly this answer got here too previous due for you i can not see the drawing. however the foremost to remedy it is that the momentum alongside the unique path of holiday could be conserved.