How do you "foil" this equation?
2007-05-17 14:58:58 · 4 answers · asked by Adam T 1 in Science & Mathematics ➔ Mathematics
assuming it's ((2)(x^2)) and not (2x)^2;
(x^2)(2x^2)
(x^2)(2)(x^2)(x^2)
2(x^2)((x^2)^2)
2(x^2)(x^4)
2(x^6)
2007-05-17 15:08:52 · answer #1 · answered by Lucifer 4 · 0⤊ 0⤋
I wouldn't really say you could foil this in terms of the traditional 'foil' method. All you can really do with this one is multiply 2x^2 by x^2, which will get you 2x^4.
2007-05-17 22:10:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
= x² X 2x²
= 2 X x² X x²
= 2x^(4)
2007-05-18 09:03:02 · answer #3 · answered by Como 7 · 0⤊ 0⤋
You can't F.O.I.L. this equation because you are only multiplying 2 monomials. You can only use the F.O.I.L. method when multipying 2 polynomials.
2007-05-17 22:12:08 · answer #4 · answered by tintanboi 3 · 0⤊ 0⤋