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Can someone tell me the complete iconic equation for the follow four problems?

1) Na2C2O4 + Ba(NO3)2 --> Na(NO3)2 + COBa

2) Na2SO4 + Ba(No3)2 --> Na(NO3)2 + SOBa

3) NaC2O4 + BaCl2 ---> NaCl + COBa

4) NaSO4 + BaCl --> NaCl + SOBa

2007-05-17 14:40:48 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Chemistry is not a religion, so we don't have Iconic equations. We do have ionic relations for chemicals that act as ions in solution. You have made many elementary mistakes, so let me bring them to your attention.

THE ANION IS ALWAYS FIRST, Here your anions are the sodium and barium ions. So Na and Ba are always put ahead of the cation.

EQUATIONS ARE BALANCED. If you start with 1 C2O4 -2 ion on one side, you should have 1 C2O4 -2 ion on the other side. I like to call this ion (COO-)2 to better show the structure of the ion.

IONS THAT ARE UNCHANGED DON'T CHANGE THEIR IONIC CHARGE. For example, oxalate (COO-)2 always keeps a -2 charge.
Sulfate (SO4=) has a -2 charge. Same with Na+ and Ba+2.

IN AN IONIC REACTION, ANIONS ARE BEING SWITCHED AND ARE NOT REACTED UPON. One reason we pick on barium ion is because its
salts are relatively insoluble compared to salts of sodium.

With that, your first equations should read:
2 Na+ + (COO-)2 + Ba+2 + 2(NO3-) -->
2 Na+ + 2 (NO3-) + Ba+2 + (COO-)2

2007-05-17 14:59:33 · answer #1 · answered by cattbarf 7 · 0 0

I hate this. GL

2007-05-17 21:53:53 · answer #2 · answered by ? 3 · 0 0

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