log 45=log 5 +2 log 3
log 45=3.6+2*1.4
log 45=6.4
2007-05-17 14:27:10
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answer #1
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answered by yupchagee 7
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Using the rule of log that
log a + log b = log a*b
you can see that
log 45 =
log 3*3*5 =
log 3 + log 3 + log 5 =
1.4 + 1.4 + 3.6 =
6.4
2007-05-17 14:29:00
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answer #2
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answered by Phineas Bogg 6
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log 45
= log 5 + log 9
= log 5 + (2 log 3)
= 3.6 + (2 * 1.4)
= 3.6 + 2.8
= 6.4
2007-05-17 14:31:14
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answer #3
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answered by boo0726 3
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log (45)
= log(3² x 5)
= log(3²) + log 5
= 2.log 3 + log 5
= 2.8 + 3.6
= 6.4
2007-05-18 02:27:37
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answer #4
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answered by Como 7
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A better problem would be to find the base. Anyway, since 3x3x5=45, we add the corresponding logs: 2x1.4+ 3.6 = 6.4
2007-05-17 14:28:28
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answer #5
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answered by cattbarf 7
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log(45)~1.6532125137753
2007-05-17 14:28:13
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answer #6
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answered by guille4ty 2
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