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(-3,0), (-2,1), (-1,2), (0,3), (1,2), (2,1), (3,0)...

2007-05-17 14:10:09 · 3 answers · asked by ? 1 in Science & Mathematics Mathematics

My math book doesn't show crap Hayley, now stop answering questions you don't know the answers to just to get a couple of stupid points!

2007-05-17 14:17:00 · update #1

So -|x| flips it over, huh? I knew there was a plus three in there but I didn't know how to flip it upside down. Ok, Pascal, thanks! I'll be back later on to give dub your answer the best! :D

2007-05-17 14:33:39 · update #2

So -|x| flips it over, huh? I knew there was a plus three in there but I didn't know how to flip it upside down. Ok, Pascal, thanks! I'll be back later on to dub your answer the best! :D

2007-05-17 14:34:00 · update #3

3 answers

Looks like all of the points are consistent with -f(x) + 3.

2007-05-17 14:27:49 · answer #1 · answered by Pascal 7 · 0 0

For f(x) = |x|, the lowest point is the origin. Also, the slope to the right of the origin is 1 and to the left is -1.

By looking at the given points, you can see that (0, 3) is the highest point. Also, the slopes are 1 for each pair to the left of (0, 3) and -1 to the right of (0, 3).

This tells us two things. The graph has been flipped in the x-axis (to make a "highest" point) and the graph has been shifted up 3. Thus, the new equation is y = -|x| + 3. Hope this helps.

2007-05-17 14:33:46 · answer #2 · answered by Lee 3 · 0 0

You need to reflect f(x) across the x-axis and then translate the result three units up.

2007-05-17 14:42:39 · answer #3 · answered by ironduke8159 7 · 0 0

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