So I've figured out how to find the angles when it is just a number like 42° to find, but I can't figure out how to solve them when there is an equation in parenthesis like (2x + 40)°. Help?
2007-05-17 13:01:32 · 4 answers · asked by Kitkat 2 in Science & Mathematics ➔ Mathematics
It's the same process. You subtract the measure of the angle from 90.
For 42°, you do:
90 - 42 = 48
For (2x + 40)°, you do:
90 - (2x + 40) = 90 - 2x - 40 = 50 - 2x
As we don't know what x is, this is as simplified as the complementary angle gets.
2007-05-17 13:04:04 · answer #1 · answered by NSurveyor 4 · 0⤊ 0⤋
The complement of an angle θ is by definition 90°-θ. Period. So all you have to do to find the complement of 2x+40° is write 90°-(2x+40°). And then simplify a bit: distributing the negative gives 90°-2x-40°, and then combining like terms gives 50°-2x. It really is that simple.
2007-05-17 20:07:29 · answer #2 · answered by Pascal 7 · 0⤊ 0⤋
Ignore the 40 and figure out the angle of 2x. Once you have that then bring the 40 back in and solve.
2007-05-17 20:05:54 · answer #3 · answered by Cool Nerd At Your Service 4 · 0⤊ 0⤋
To find the complement of that, just do 90-(whatever is in parentheses). In this case, 90-(2x+40), or 90-2x-40 (don't forget to distribute the negative!), which is 50-2x.
2007-05-17 20:06:49 · answer #4 · answered by Y^2 2 · 0⤊ 0⤋