solve the radical equation 2y=√5y+6
the 5y+6 is all under the radical
if there's no solution, write no solution
PLEASE SHOW ALL WORK!!!!!
thanks
2007-05-17 12:34:17 · 3 answers · asked by dancinkitty0510 3 in Science & Mathematics ➔ Mathematics
Square both sides
4y^2 = 5y + 6
4y^2 - 5y -6 = 0
(4y + 3)(y - 2) = 0
y = -3/4, y = 2
only y = 2 works
2007-05-17 12:40:50 · answer #1 · answered by richardwptljc 6 · 1⤊ 0⤋
First, you want to get rid of the radical. This can be done by squaring both sides to get:
4y^2=5y+6
Bring everything to one side to get this to be a quadratic equation in standard form.
4y^2-5y-6=0
Factor:
(4y+3)(y-2)=0
Solve for y.
y=-3/4
y=2
y={-.75, 2)
2007-05-17 12:39:48 · answer #2 · answered by amleo6 2 · 0⤊ 0⤋
Good Luck with that problem...doesn't seem to hard. But I would have to write it all out.
2007-05-17 12:39:13 · answer #3 · answered by lynn 4 · 0⤊ 2⤋