Math whiz, please check my work (multiplying monomials):?

Question

Question:

-2(4x + 3)

My answer: 8x + 6

Question#2
y( y + y³)

My Answer: y + y4 (small 4)

thank you...

(no, I'm not a kid, I'm a parent trying to help her child)!! I'm the perfect example of either use it or lose it! I completly forget how to do this. I"m trying to use the "FOIL" method.

You guys are so great, thank you very much for the answers and explanations!!!!

Answer 1

well i am a kid but not as idotic as you think

#2:
y²+y^4

and #1:
-8x-6

Answer 2

Both of these problems use distribution rather than the FOIL method. The FOIL method is when you are multipling two binomials together (i.e. (x+2)(x-1)).

1. Answer should be -8x - 6...you forgot to also distribute the negative.

2. Distribute the y to both terms: y*y=y^2 and y*y^3=y^4, so the answer should be y^2 + y^4.

You'll get it back! :)

Answer 3

Question 1:
For "-2(4x+3)" remember that when you distribute the two to the rest of it, you also distribute the negative, so it would be:

-2*4x+ -2*3 which is
-8x-6

for Question 2:
you were close!
When you distribute the y, you also distribute it to the first y, so it would be

y^2+y^4 (in some calculators, "^" is used as "to the power of")

I hope you understand it, feel free to e-mail me if you need more help!

Answer 4

Question 1: should be -8x - 6
Question 3: should be y^2 + y^4

Answer 5

1. You forgot the negative sign: -8x-6

2. y^2+y^4: make sure you multiply the first y with y like you did y^3.

FOIL means First Inside Outside Last. In your first brackets multiply the first number or variable in the equation bby the whole second brackets. Then do the same with the second number or variable in the first bracket. Example:

(x+1)(x+2):
First with the x:
x*x=x^2 (x squared)
x*2=2x

Now with the 1:
1*x=x
1*2=2

Since the first bracket had x+1 that means you add both brackets:

(x^2+2x)+(x+2) = x^2+2x+1+2=x^2+3x+2


Small yet simple mistakes. Other than that great job. :-)

Answer 6

Question 1: should be -8x - 6
Question 3: should be y^2 + y^4

Answer 7

Do the numbers to the power and multiply them; then multiply the exponent outside each parenthesis by the exponents inside; thenadd the exponents for the variables 25^3 = 15625; 1/5 ^ 2 = 1/25; 15625 • 1/25 = 625 (a^2b) ^3 = a^6b^3; abc all squared is a^2b^2c^2 so 625 a^8b^5c^2 unless you meant the second to be 1 over 5abc and not 1/5 times abc, in which case subtract the exponents at the end since it's division 625 a^4bc^-2 which is 625a^4b over c^2

Answer 8

1) Incorrect. Because it's -2, the answer is -8x - 6.
2) It would be y^2 + y^4. The y on the outside must be multiplied by everything on the inside.

Answer 9

1)-2(4x+3)
Multiply both terms:
(-2*4x)+(-2*3)=
-8x-6

2)y(y+y^3)
Same method as number #1:
y^2+y^4

Answer 10

The first one is wrong...-2(4x+3)= Should be -8x-6, watch for negative..
Remember: Negative times/devide positive is NEgative....
Negative times/divide negative is POSITIVE..

.. let me see the rest... hold on.. someone is calling me.. hehe

Okay the second one is.. y(y+y^3)= Should be y^2+y^4.....

Be proud and good luck to you... =)

Answer 11

lol @FOIL...
I am sure someone will give you the right answer.

1. -8x - 6
2. y^2 + y^4......^2 means small 2, and ^4 means small 4.