x^2 - x = 0
Factor out the common x
x(x - 1) = 0
Multiplicative Property of Zero says any number time zero equals zero
so if x = 0 then
0(0 - 1) = 0
0(-1) = 0
0 = 0
and if x = 1 then
1(1 - 1) = 0
1(0) = 0
0 = 0
so x = either 0 or 1
2007-05-17 12:05:17
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answer #1
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answered by Poetland 6
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x^2 - x - 20 = 0 You have to find two factors of -20 that add up to -1 and multiply to give -20. The factors of 20 are 1 * 20, 2 * 10 and 4 * 5. We know that 4 - 5 = -1 and 4 * -5 = -20, so the factors are (x + 4) and (x - 5). So, (x + 4) (x - 5) = 0 Either x + 4 = 0 or x - 5 = 0 x = -4 or x = 5. I hope that helps. :) ILoveMaths07.
2016-05-22 00:29:59
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answer #2
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answered by ? 4
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you take the x out, so the new equation will be:
x*(x-1)=0
To make this equation happens, either x or x+1 will equal to zero. So we will find 2 solutions, which are:
x=0 or x-1=0 which x=1
So the final solutions are: 0 and 1.
2007-05-17 12:08:43
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answer #3
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answered by Salinda M 2
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x^2-x=0
x(x-1)=0 x=0 x-1=0 x-1+1=0+1=x=1
x=0 x=1
2007-05-17 12:29:08
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answer #4
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answered by Dave aka Spider Monkey 7
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Factor
x^x - x = 0
x(x-1) = 0
x = 0, x = 1
2007-05-17 12:03:34
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answer #5
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answered by richardwptljc 6
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x^2 - x = 0
x^2 = x
x= 1 or -1
2007-05-17 12:07:10
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answer #6
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answered by dave r 2
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Question is not clearly worded.
Recast the question in an intelligible way & present.
2007-05-17 12:14:19
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answer #7
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answered by Anonymous
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or you could use the quadratic formula, but factoring's easier
2007-05-17 12:04:52
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answer #8
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answered by jimbothe_smartguy 2
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ok
the equation put easily is..
X times X -X=0
now.....
basically.....
well.....
the only posible answers r 1, 0, and -1
its sorta.....
obvious.....
no offence.
2007-05-17 12:06:30
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answer #9
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answered by Anonymous
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