question 4?

Question

A dog sits 1.5m from the center of a mery go round and revolves at a tangenital speed of 1.8m/s. If the dog's mass is 18.5kg, what is the magnitude of the centripital force of the dog.

STEP BY STEP EXPLAINATION PLEASE IN "ENGLISH"

Answer 1

When a body moves on a circular path with constant speed,its motion is called uniform circular motion.

As direction of motion is continuously changing,the velocity in circular motion is variable.

In circular motion, the acceleration is called centripetal acceleration because direction of acceleration is towards the center of the circle at all points of the circular path.

If 'r' is radius of circular path, 'v' is speed the centripetal acceleration 'a' = (v^2) /r

The force which causes centripetal acceleration in circular motion is called centripetal force F

Here radius 'r'= 1.5 m

speed 'v' =1.8 m/s

Centripetal acceleration 'a ' = 1.8 * 1.8 /1.5

Centripetal acceleration 'a ' = 2.16 m /s^2

Mass of the dog =18.5 kg

Centripetal force = (mass'm') ( Centripetal acceleration'a ')

Centripetal force on the dog =18.5 * 2.16 = 39.96 newton

Answer 2

Equation for Force:
F=ma (newtons second law)

acceleration in a circular motion is a = (v^2)/r, where r is radius of circle (1.5m in this case) and v is the tangential velocity (1.8m/s in this case)

so, F = m x (v^2)/r

F = (18.5 x 1.8^2) / 1.5

hope that helps!