here is the question: A rope attaches a tire to an overhanging tree limb. A girl swinging on the tire has a centripetal acceleration of 3.0 m/s (squared). If the length of the rope is 2.1m what us the girl's tangetential speed. Please can u explain 2 me how to get the answer.
2007-05-17 09:36:13 · 2 answers · asked by damigurl05 1 in Science & Mathematics ➔ Physics
a=3m/s^2
r=2.1m
the equation is a=v^2/r
so....
v = sqrt(a*r)
v = sqrt(2.1*3)
v = sqrt(6.3)
and of course the units of v is m/s
2007-05-17 09:41:47 · answer #1 · answered by electric 3 · 0⤊ 0⤋
Centripetal acceleration = a = v^2/R; where R is the length of the rope = 2.1 m. Therefore the tangential velocity of the swinger is v = sqrt(aR); where a = 3 m/sec^2. You can do the math.
You have to know that centripetal acceleration is v^2/R and that v = the tangential velocity at the tip of R away from the axis of the swing.
2007-05-17 16:46:23 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋