Find two numbers whose sum is 42 and such that one is 2 times as large as the other?
2007-05-17 09:33:26 · 10 answers · asked by aklepard 1 in Science & Mathematics ➔ Mathematics
14 + 28 = 42
28 = 2 * 14
2007-05-17 09:37:14 · answer #1 · answered by Demiurge42 7 · 0⤊ 1⤋
28+14
2007-05-17 09:43:51 · answer #2 · answered by frances_lambert02 1 · 0⤊ 0⤋
28 and 14
2007-05-17 09:39:10 · answer #3 · answered by Nicola W 3 · 0⤊ 0⤋
28 and 14
2007-05-17 09:37:13 · answer #4 · answered by Not Ready Just Yet 2 · 0⤊ 0⤋
28 and 14
2007-05-17 09:36:25 · answer #5 · answered by jefedrum 2 · 1⤊ 0⤋
7 and 6
2016-05-21 22:54:16 · answer #6 · answered by ? 4 · 0⤊ 0⤋
2x + x = 42
You should be able to solve it from here. Basically 3x = 42. So divide 42 by 3 and you get x = ? Then apply your answer in the place of the x and see if it checks out.
2007-05-17 09:39:09 · answer #7 · answered by lastcaress21 3 · 0⤊ 0⤋
write an equation and then solve for your variable, then multiply it by two to get the next number you need as seen below:
x + 2x = 42
x( 1 +2)
3x = 42
x=42/3
x = 14
14+ 28 = 42
2007-05-17 09:38:04 · answer #8 · answered by Anonymous · 0⤊ 0⤋
let the numbers be x and y. Assume x is smaller, so y = 2x.
so x + 2x = 42 or 3x = 42 & x = 14, so they are 14 and 28
ALWAYS start with giving the numbers labels and turning the words into equations.
2007-05-17 09:37:19 · answer #9 · answered by doctor risk 3 · 1⤊ 1⤋
OK, we have an equation with 2 unknowns.
x + y = 42 but they also tell us that one of these numbers is twice the value of the other so let's say y = 2x
so x + 2x = 42
3x = 42
x = 14
y = 28
2007-05-17 09:37:32 · answer #10 · answered by James L 2 · 0⤊ 1⤋