How do you simplify this equation?

Question

a
__
b+1
___
1+c
___
x

Answer 1

I'm assuming you mean...

a/(b+1) / (1+c)/x

First: find the greatest common denominator which, is x(b+1)

Sec: multiply the missing terms with each denominator & corresponding numerator to get the greatest common denominator.

(x)[a/(b+1)] / (b+1)[(1+c)/x]

[ax/x(b+1)] / [(b+1)(1+c)/x(b+1)]

Third: rule - you can't divide fractions. multiply the 1st fraction with the reciprocal of the 2nd fractions - flip the 2nd fraction.

[ax/x(b+1)] * [x(b+1)/(b+1)(1+c)]

Now, cross cancel "like" terms.

(ax/1) * [1/(b+1)(1+c)]

ax/(b+1)(1+c)

Answer 2

I am reading this as:-
[ a / (b + 1) ] / [ (1 + c) / x ]
= ax / [ (b + 1).(c + 1) ]

Answer 3

division is like multiplying by the reciprocal...

so [a/(b+1)]*[x/(1+c)]

=ax/[(b+1)(c+1)]
=ax/[b²+b+c+c²]

You COULD multiply by conjugates, but that's not going to simplify it any more, so that's the answer

Answer 4

I interpret this as :
a/(b+1) divided by (1+c)/x
If this interpretation is correct, then we have:
a/(b+1) times x/(1+c)
=ax/[(b+1)(c+1)]

Answer 5

ax/(b+1)(1+c)

That's as simple as I can get it.

Answer 6

that's very ambiguous... try rewriting it so you can see which parts are fractions?

i.e. is it:

(a) / (b+1)
----------
(1+c)/(x)

or:

(a) / ( (b+1)/ ((1+c)/x) )

they're different, please make clearer!

if you have fraction such as:

a
-------
(b / c)

you can effectively "move the bottom part up" to get:

a * c
-------
b

maybe that'll help here?

Answer 7

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