2007-05-17 05:50:53 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
it varies with the temperature. At room temperature,
pOH=7
pH=7
[H3O+]=10^ -7
[OH-]=10^ -7
2007-05-17 06:10:11 · answer #1 · answered by avinash a 1 · 1⤊ 0⤋
a million. pH = 7.ninety pOH = 14 - pH a. [H3O+] = [H+] so [H+] = 10^(-pH) b. [OH-] = 10^(-pOH) c. If [H+] is > 1e-7 then it truly is hardship-free, no matter if it truly is > 1e-7, then it truly is acidic 2 is performed an same way
2016-11-04 05:56:40 · answer #2 · answered by ? 4 · 0⤊ 0⤋
nuetral solution pH and pOH of 7, pH=-log[H], so you calculate the [H] and [OH], they will be the same.
2007-05-17 05:53:28 · answer #3 · answered by jcann17 5 · 0⤊ 0⤋
pOH = 7
pH = 7
And the [OH-] and [H3O+] are equal to each other.
2007-05-17 05:55:01 · answer #4 · answered by delilah 2 · 0⤊ 0⤋
7,7, 1*10^-7, 1*10^-7
(at 25C)
2007-05-17 05:53:51 · answer #5 · answered by chemmie 4 · 0⤊ 0⤋
7,7, 10^-7, 10^-7
2007-05-17 05:58:15 · answer #6 · answered by ag_iitkgp 7 · 0⤊ 0⤋
pOH=pH
2007-05-17 06:34:18 · answer #7 · answered by waffles 2 · 0⤊ 0⤋