4x^2 = 4*x^2
5x^2 = 5*x^2
4x^2 times 5x^2 = 4 * x^2 * 5 * x^2
= 20 * x^2 * x^2
= 20x^4
2007-05-17 05:37:36
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answer #1
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answered by Akilesh - Internet Undertaker 7
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(4x^2)(5x^2) = Commutative property of multiplication
(4)(5)(x^2)(x^2) = Constant times constant
20(x^2)(x^2) = Multiplication of same base is the addition of exponents
20(x^(2+2)) = 20x^4
20x^4
2007-05-17 05:36:33
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answer #2
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answered by Poetland 6
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you multiply the bases first 4 times 5 = 20
then the xs: x to the power 2 times x to the power 2 = x to the power 4
so the answer is 20 x to the power 4
2007-05-17 05:37:32
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answer #3
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answered by nour_blue4ever 2
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Multiply the numbers first.
5*4 = 20
then multiply the x's:
x^2 * x^2 = x^(2 + 2) = x^4.
now put together: 20x^4
2007-05-17 05:35:21
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answer #4
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answered by peateargryfin 5
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when ur multiplying two variables with two exponents that are the same, u add the exponents together and mulitply the two variables together and u should come up with:
20x⁴
2007-05-17 08:46:41
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answer #5
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answered by $g_monEy$ 2
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20x^4
2007-05-17 05:35:20
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answer #6
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answered by Traqqer 2
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20x^4
2007-05-17 05:35:08
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answer #7
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answered by emp211 3
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http://groups.yahoo.com/group/gk_maths ......Join to this Group of maths..It can solve all your problem
2007-05-17 05:40:44
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answer #8
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answered by GURUBHAI 1
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