2007-05-17 05:08:26 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Anhydrous copper sulphate is white and turns blue in the presence of water.
Your experiment would show 1) the presence (or not) of water
2)the presence (or not) of carbon dioxide. (CO2 is the ONLY gas to turn limewater milky).
2007-05-17 23:28:00 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Anhydrous Copper(II) Sulphate is the test for water (turns from white to blue in the presence of water), and limewater is the test for carbon dioxide (Forms a milky white percipitate), therefore, this is the test for the presence of water vapour and carbon dioxide
2007-05-18 18:09:33 · answer #2 · answered by tinned_tuna 3 · 0⤊ 0⤋
Got it! Assuming it's to do with combustion of a hydrocarbon.
Then passing the products ie. gasses over anhydrous copper II sulphate first would show water in the form of steam/vapour is produced, otherwise bubbling the gasses through lime water first would contaminate the products with water vapour FROM the lime water.
2007-05-18 13:25:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
To absorb either water or NH3.
2007-05-17 12:33:16 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋
For what purpose would one do this?
2007-05-17 12:16:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋