Can someone solve this problem for me?
The length of a table - tennis table is 1ft less than twice the width of the table. Let w represent the width of the table - tennis table. Express the area of the table in terms of the variable w.
2007-05-17 04:11:13 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
length = 2w-1
area = length • width
area = (2w-1)(w) = 2w² - w
2007-05-17 04:15:26 · answer #1 · answered by Philo 7 · 1⤊ 0⤋
L=2w-1
2007-05-17 04:14:59 · answer #2 · answered by colorsonfriday 2 · 1⤊ 0⤋
W = width
length L can be given as
L = 2*W - 1 = 2W - 1
area = L * W = (2W - 1) * W
= 2W^2 - W
it can also be written as = W(2W-1)
2007-05-17 06:52:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
ok let us see what is area of the tennis ...
let l be the lenght and w be the wirgth then
area = l x w (as area means to dimentions and in the case these are assumed to be abstract i.e l is straight length and so the w)
so it will be as
area = (l-1) x (2w)
area = (2l - 2) x w
hope it is enough answer
2007-05-17 04:45:40 · answer #4 · answered by Big brother 1 · 0⤊ 0⤋
2w-1=L, where L=length
2007-05-17 04:54:53 · answer #5 · answered by thegamerdug 3 · 0⤊ 0⤋
A=W*(2W-1)
2007-05-17 04:19:49 · answer #6 · answered by Georges 3 · 1⤊ 0⤋
FYI 9'x5'
2007-05-17 04:21:23 · answer #7 · answered by Anonymous · 0⤊ 0⤋