A kite has diagonals 9.2 ft and 8 ft. What is the area of the kite?
A. 36.8 ft2
B. 8.6 ft2
C. 73.6 ft2
D. 34.4 ft2
2007-05-17 03:50:52 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Pretend the kite is made of 4 right-angle triangles, where the cross of the two diagonals makes 4 right-angles.
Area of those triangles is half one RA side times the other.
Total heights is 9; total widths is 8.2
9*8.2*1/2 = 36.8 which is (A).
Or, draw a box 9x8.2; draw a cross in the middle so you get 4 littler boxes. make each of those boxes a triangle by drawing the diagonals. the inside triangles give you the kite. So the kite area is half the area of a box 9x8.2 !
2007-05-17 04:00:41 · answer #1 · answered by Anon 7 · 0⤊ 0⤋
Not to confuse you with formulas, here's an easy idea:
use those two diagonals to divide the kite into 4 right triangles. Next, what do you get if you flip one of the top two triangles onto the other one, and do the same with the botttom half of the kite? 2 rectangles. You should notice that the sides of these rectangles are one half each of the two diagonals, i.e. 4 ft. x 4.6 ft. If you multiply that (2x, once for each rectangle) and add up the results, you will get your answer.
2007-05-17 11:04:14 · answer #2 · answered by Lela 1 · 0⤊ 0⤋
Area of a kite = (1/2)* product of its diagonals
= (1/2) * 9.2 * 8
= 36.8ft^2
The answer is (a)
2007-05-17 10:54:40 · answer #3 · answered by gudspeling 7 · 0⤊ 0⤋
Assuming your kite is a generic paralleogram, you can chop it up into two isoceles triangles with base 8 ft. and combined height 9.2 ft.
area = 1/2 * base * height
I will answer: "A"
2007-05-17 10:56:00 · answer #4 · answered by not gh3y 3 · 0⤊ 1⤋
Pretend the kite is made of two triangles back to back. That should get you your answer.
2007-05-17 10:54:37 · answer #5 · answered by pob14 4 · 0⤊ 0⤋
A. 36.8 ft2
2007-05-17 10:56:41 · answer #6 · answered by asilmarie83 2 · 0⤊ 0⤋