4-3x=2x^2 solve by using the quadratic formula.?

Question

solve by using the quadratic formula.

Answer 1

Well, first things first, you have to set it equal to zero.

4-3x=2x^2
becomes

0=2x^2 - 4 + 3x

Then use the quadratic formula.

Answer 2

Ok...
What does the quadratic formula look like?
x = (-(b) ±√[(b)² - 4(a)(c)])/2(a)

What are the a, b and c?
Well, if you can get an equation into the form
ax² + bx + c = 0
a is the coefficient of the x² term, b is the coefficient of the x term, and c is some constant

Plugging these values into the quadratic equation and doing some arithmetic, should give you the value of x.

Problem
4-3x=2x^2
Doesn’t look much the form (ax² + bx + c = 0) we want.
So let’s get everything over on one side.
Add -4+3x to both sides
0 = 2x² + 3x – 4
Better? Ok…
2x² + 3x – 4 = 0
How’s that?
a = 2, b=3, and c= -4

Substituting
x = (-(3) ±√[(3)² - 4(2)(-4)])/2(2)
x = (-3 ±√[9 - -32])/4
x = (-3 ±√[41])/4

I'd leave i like that.
But, if you want numeric answers, feel free to use your calculator.

Answer 3

The quadratic formulation is -B+-sqrt(B^2-4(A)(C)/2(a) So, A = The variety in front of the x^2 B is the variety in front of the x C is the variety and not using a variable. So, your A, B and C may be a million, -8, and -4 -B, may be beneficial 8. Then (-8)^2-4(a million)(-4) might equivalent 80 So, 8 Minus the sq. root of 80 equals -.94427, then you definately divide that with the aid of 2a, it is two. So your adverse answer may be -.4721. 8+sqrt(80)/2 Equals 8.4721. Your answer may be -.4721, and eight.4721

Answer 4

convert the formula as

2x^2 + 3x - 4 = 0

use the formula (-b + sqrt(b^2 - 4ac))/2 and (-b - sqrt(b^2 - 4ac))/2

the answers that you will get will be 4.70156 and -1.70156 approx

you will find this answer to be correct as addition of both numbers should be equal to b which is 3 and the multiplication of the two numbers should be equal to a*c which is 2 * (-4) which is -8.

4.70156 + (- 1.70156) = 3 which is b
4.70156 * (-1.70156) = -8 which is a * c

Answer 5

2x^2 +3x - 4 = 0 set to zero
- 3/4 +/- sqrt 9 - -32 / 4
x= -3/4 +/- sqrt 41 / 4

Answer 6

4-3x = 2x^2

Set the equation to standard form
ax^2 + bx+ c = 0

2x^2 + 3x - 4 = 0
a = 2
b = 3
c = -4
Quadratic formula:
x = (-b +/-sqrt b^2 - 4ac))/2a
x = -3 +/- sqrt 3^2 - 4(2)(-4))/2(2)
x = (-3 +/- sqrt 9 + 32)/4
x = -3 +/- sqrt 41/4
x = -3 +/-6.403/4
x =( -3 + 6.403)/4
x = 3.403/4
x = .8508
Another root
x =( -3 -6.403)/4
x = -9.403/4
x = -2.3508
x = .8508 and - 2.3508

Answer 7

2x² + 3x - 4 = 0
x = [- 3 ± √(9 + 32)] / 4
x = [- 3 ± √41] / 4
x = 0.85, x = - 2.35

Answer 8

2x^2+3x-4=0
a=2
b=3
c=-4

x = [-3±sqrt(3^2 - 4*2*(-4))]/4
=[-3±sqrt(41)]/4
=0.8508 (approx) and -2.3508 (approx)