How do i find an equation for the line perpendicular to y=1/2x+1, passing through (10,6)?

Answer 1

y intercept equation: y = mx + b
m is the slope and b is the y intercept
for the given equation: m = 0.5 and b = 1
to get the perpendicular, get the negative inverse of m
m(perpendicular) = -1/(0.5) = -2
now perpendicular equation: y = -2x + b
to get b, use (10, 6)
6 = -2(10) + b
b = 26

So perpendicular equation: y = -2x + 26

Answer 2

Gradient of perpendicular line = 1/2

Grandient of line = -2 Inverse it and change sign

recall formula (Y-y) = m(X-x)
Equation of line = (Y-6) = -2(X-10)

Expand brackets
Y-6 = -2X+20

Send the -6 to the right hand size
Y = -2X + 26

Answer 3

As the line is perpendicular to y = (1/2)x + 1, then its gradient is: m x (1/2) = -1 => m = -2

y = mx + c
6 = (-2)(10) + c
6 = -20 + c
c = 6 + 20
c = 26

So the equation is: y = -2x + 26

Answer 4

nicely for the slope of the perpendicular line, you want the different reciprocal (also familiar as turn-o substitute-o) of the unique slope. So -a million/2 flipped and altered might want to easily be 2. so a lengthy way it truly is y=2x + b. to discover "b" (your y-intercept) plug contained in the point (2,-3) into that formula. supplying you with: -3=2(2) + b. in case you settle on that out, you get b=-7. Your end formula might want to be: y=2x-7 desire that helped!

Answer 5

Read this as:-
y = (1/2).x + 1--------m = 1/2
Gradient of perpendicular = - 2
y - 6 = - 2.(x - 10)
y = - 2x + 26 is equation of required line.

Answer 6

first fnd da gradient which has in dis case is -2(cuz da gradient of ur line is 1/2)
then use da formula
y=ax+b
a=-2
then put (10,6) in da equation to find b
6=-2*10+b therefor b=26therefor da equation is y=2x+26
u hav to choose me as da bst answa

Answer 7

there must be a formula to find it out in Algebra,I would have known it some decades ago, late forties and early fifty but I am unable to think and work it out.