math geniuses needed please, I really can use your help. I am so lost in solving the quadratic by completing?

Question

the sqaure

here is the question

x^2-10x+16=0

can someone help me please? explain the steps to me.

Answer 1

This is pretty simple by using the shoelace method.

x -8 | 8x

x -2 | 2x
---------------
x^2 16 | 10x

(x - 8)(x-2)=0, therefore x=8 or x=2
What you need to do is make sure that the third row shows what is in your question. The third column should add up to 10x.
In the first column, separate the square. You see that I have separated x^2 into x * x
In the second column, separate the constant, which is 16. Now you have to think. What can you use? It has to satisfy the conditions of
a*b=16 and a+b=10
The factors of 16 are 1*16, 2*8, 4*4
Yes, got it. 2+8=10!
So you put that in the shoe lace.

But... you have to get a negative sign for -10x.
x * 8 = 8x
x * 2 = 2x
This is 10x without the negative sign.

Oh so, if you take -8, and -2... -8 * -2 = 16 (neg * neg = pos)
x * -8 = -8x
x * -2 = -2x
It works! Add them together and you get -10x!
You got the answer. (x - 8)(x-2) = 0 That means either (x-8)=0 or (x-2)=0 (because a*0=0) so if it is the first one, then x = 8, if it is the second one, then x = 2

Hope it helps. Good luck.

Answer 2

Solving by completing the square includes the following steps :

Add and subtract the square of half the coefficient of x to the LHS.

x^2 - 10x + 16 + 25 - 25 = 0

Rearranging :

x^2 - 10x + 25 - 25 + 16 = 0
(x^2 - 10x + 25) - 9 = 0
(x - 5)^2 - 3^2 = 0

Use the identity a^2 - b^2 = (a + b)(a - b)

(x - 2)(x - 8) = 0

This gives x = 2, 8

Hope this helps.
If you have any query, you may mail me at [e-mail]

Answer 3

First you find factors of the last digit. In this case, 8 and 2 (8 x 2).

Then, you take those factors and find the middle term. (negative x negative = positive; therefore, -8 X -2 = 16)

So, you end up with (x-8)(x-2)=0.

To find what X equals, you put each polynomial equal to 0.
So, x-8=0. If you solve this, it is x = 8.

Likewise, x-2=0; x=2

So, the answer for the problem is X = 8 and 2

Answer 4

x^2-10x+16=0

To complete the square add 9 to both sides

x² - 10x+16+9 = 0+9

x² -10x + 25 = 9

(x - 5)² = 9

Take the square root of both sides

(x - 5) = 3 or -3

add 5 to both sides

x = 8 or 2
.

Answer 5

You want to factorise the equation..i.e. find out what it was before:
The quadratic formula is: ax^2 + bx+ c=0

here x^2 -10x +16=0
so a=1 , b= -10 and c =16

You can factorise it via ---> (x - 8 ) (x - 2)

x * x = x^2 : -2 * x = -2x : -8 * x = -8x and -8 * -2= 16

so therefore we have x^2 -2x -8x + 16 =0
Which is x^2 -10x+16


hope this helps.

Answer 6

ok, first, once you positioned up those, do no longer say you're fixing the quadratic equation.Say you're fixing a quadratic. human beings gets perplexed. here we pass. 3x^2-10=x^+214 Fisrt, circulate each and all of the X^2 words to one section and each and all of the constants to one section. Constants = quantity with out a coefficient. 2x^2=224 Divide the two factors by way of 2, so which you're able to do away with the coefficient (the quantity in front of x^2) x^2=112 take the sq. root of the two factors. x=±8?2

Answer 7

x^2 - 10x + 16 = 0
x^2 -8x -2x + 16 = 0
x(x - 8) -2(x - 8) = 0
(x -8) (x - 2) = 0
therefore x -8 = 0 or x -2 = 0
therefor x = 8 or x = 2

Answer 8

x^2-10x+16=0
x(x-10)+16= 0
(x-5)^2-(5^2)+16= 0
(x-5)^2-25+16= 0
(x-5)^2-9= 0

Answer 9

Ans: (x-8)(x-2)=0

Answer 10

a=2 b= -10 c=16
substitute for d
and then find x u should get 2 solutions