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theta = 15° 30'
The distance (horizontal) is simply
120 * tan (90 - theta)

show me the solution

2007-05-16 22:35:56 · 2 answers · asked by JESS 1 in Science & Mathematics Mathematics

2 answers

theta = 15° 30'

then 90 - theta = 90 - 15° 30'

15° 30' = 15.5°, as 30' = 0.5°

tan(90 - 15.5) = tan(74.5)

distance = 120*tan(74.5)

distance = 120*3.606 = 432.71
.

2007-05-16 23:06:38 · answer #1 · answered by Robert L 7 · 0 0

15° 30' = 15.5°
tan(90° - 15.5°) = 1/tan(15.5°)
120/tan(15.5°) = 432.7060

2007-05-17 06:00:19 · answer #2 · answered by Helmut 7 · 0 0

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