This is the same as solving
0.471214x^3 - 5.763154x^2 - 285.7213 = 0
There is a little-known formula for solving cubics:
http://www.math.vanderbilt.edu/~schectex/courses/cubic/
...although you will see that it is rather more complicated than the quadratic formula.
If I were doing this, I would plot the graph of
y = 0.471214x^3 - 5.763154x^2 - 285.7213
and look for how many times it crossed the x-axis for how many solutions there are.
(I just did this and it crosses once, near x = 15, concurring with previous answers. I did it on a computer and had to zoom in to confirm that it only crosses once.)
I would then use a numerical method such as Newton-Raphson
http://en.wikipedia.org/wiki/Newton's_method#Description_of_the_method
2007-05-16 21:25:44
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answer #1
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answered by joncummins1968 4
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Kinda tricky problem ain't it
Well after extensive solving I got the answer to be 14.945
If you use a scientific calculator it becomes a little easier and you still get the same answer(it continues to more places of decimals)
2007-05-17 04:50:47
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answer #2
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answered by oolala 2
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It's a cubic equation.
Anyways x=14.9452
2007-05-17 04:09:30
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answer #3
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answered by Anonymous
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it is a little complicated problem.
using a scientific calci i got x = 14.945
2007-05-17 04:28:22
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answer #4
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answered by Charu Chandra Goel 5
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x = 14.94515112
Solved numerically
2007-05-17 04:27:09
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answer #5
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answered by Helmut 7
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8 i jus worked it out sorry i cant put the work it too much
2007-05-17 04:09:18
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answer #6
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answered by winegeartr 2
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It might not have analytic solution.
2007-05-17 04:09:54
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answer #7
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answered by moosadarya 3
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x = 14.94515
2007-05-17 04:23:24
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answer #8
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answered by Zax 3
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