It depends on two factors:
as was stated above, if you are working with gas products or reactants, because adding a noble gas will alter the pressure moving the system to the side of fewer gas molecules.
However! If you should happen to be working with flouride (please don't it's very dangerous and if you do, be sure to have some calcium glucanate around) and the noble gas Xenon...then yes you can actually get a reaction. Xenon and flouride will react to from XeF2, XeF3 XeF4 and XeF6, so addition of Xe will affect the equilibrium.
To answer your question though....in any chemistry most people perform, a noble gas will only affect the position should another gas be in the system.
2007-05-16 19:49:53
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answer #1
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answered by Steven C 1
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I agree with JC. If the noble gas is going to raise the overall pressure of a closed system, then this will affect the equilibrium if any gases are involved in the reaction. Otherwise, it will have no effect.
2007-05-16 19:49:55
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answer #2
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answered by jellybeanchick 7
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Hypothetically, it may well be ununoctium, as that's the backside down on the periodic table and in team 18, notwithstanding realistically, Radon has the backside ionization power and there fore likely to ensue in chemical reactions, notwithstanding, Xenon has created the main compounds with fluorine and oxygen interior the lab and subsequently would be my ultimate guess as to which nobel gas would likely ensue in chemical reactions.
2016-12-29 07:44:45
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answer #3
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answered by letitia 3
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Only if there are unequal numbers of moles of gas on either side of the equation. Adding the noble gas will then be like increasing the pressure.
2007-05-16 19:27:26
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answer #4
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answered by Gervald F 7
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It won't because it is chemically stable. It does not eccept or give away electrons. It may increase the pressure if it is in a closed system.
2007-05-16 19:33:05
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answer #5
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answered by Darth Vader 5
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Nope. Noble gases are unreactive!
2007-05-16 19:17:48
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answer #6
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answered by Alice 2
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http://en.wikipedia.org/wiki/Le_Chatelier%27s_Principle#Effect_of_Adding_an_Inert_Gas
2007-05-16 19:37:24
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answer #7
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answered by JC 2
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