English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

4 answers

~don't think so!

2007-05-16 18:12:08 · answer #1 · answered by bobby a 4 · 0 1

Uhm... none of your answer choices have arrows dividing the products from the reactants. And you should seriously learn this material since this is relatively basic chemistry. I can assure you if you have trouble with this, chemistry class is not going to be pleasant for you. With that having been said, the correct way to work out this problem is as follows: Cl2 + 2KI ---> 2KCl + I2 KI and KCl both dissociate in solution so we get the following: Cl2 + (2K+) + (2I-) ----> (2K+) + (2Cl-) + I2 Since K+ is on both sides of the equation, we can cancel those two out to get the following: Cl2 + (2I-) ----> (2Cl-) + I2 which is your answer.

2016-04-01 05:30:13 · answer #2 · answered by Anonymous · 0 0

Cl2 + H2O <----> HCl + HClO

2007-05-16 19:34:28 · answer #3 · answered by Gervald F 7 · 1 0

I hope I'm not doing your take home test.
does hypochlorous acid ring a bell?

2007-05-16 18:16:50 · answer #4 · answered by Kent L 1 · 0 1

fedest.com, questions and answers