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I need some help well alot of help plzzzzzz



20. An ionically bonded substance and a covalently bonded substance. Label each with the substance it represents. Chemical formulas, common names and chemical names required.



36. A mixture which could be separated using paper chromatography. Define paper chromatography. Common name required.


43. A molecule with bonding that follows the octet rule. Common name, chemical name, chemical formula required.



50. The amount of NaCl produced from 10.0 g of sodium hydrogen carbonate reacting with an excess of hydrochloric acid. Assume 75 % yield. Balanced equation and calculations required. (no work, no credit, no kidding)



would you explain this 2 me also...i dont get any of them... :( im not good with chemistry things :(

2007-05-16 16:17:06 · 5 answers · asked by elaheh_hm 1 in Science & Mathematics Chemistry

5 answers

20. Ionic: Salt Sodium chloride NaCl
Covalent: Glucose "Grape sugar" C6H12O6

36. Chlorophyll a and b. Boil a lot of spinach in water. Put a drop of the solution at the "start" of the paper and watch it "develop." Go to Wikipedia for a description of paper chromatograophy and paraphrase ih your own words.

43. Methane "Natural gas" CH4 Draw a C with 4 H's on all four sides. Draw four x's to represent C electrons and four *'s to represent H electrons on all four sides between all atoms.

50. NaHCO3 + HCl ===> NaCl + H2O + CO2
Atonmic weights: Na=23 H=1 C=12 O=16 Cl=35.5 NaHCO3=84 NaCl=58.5

10.0gNaHCO3 x 1molNaHCO3/84gNaHCO3 x 1molNaCl/1molNaHCO3 x 58.5gNaCl/1molNaCl = (10)(58.5)/(84) = 6.96gNaCl

The 10g NaCl is given. The next factor comes from the formula weight of NaHCO3. The g NaHCO3 cancel, leaving mols NaHCO3. The next factor comes from the balanced equation. The moles NaHCO3 cancel, leaving g NaCl. The next factor comes from the formula weight of NaCl. The mols NaCl cancel, leaving g NaCl.

2007-05-16 16:37:26 · answer #1 · answered by steve_geo1 7 · 1 0

Chemical Scavenger Hunt Answers

2016-11-04 13:35:31 · answer #2 · answered by ? 4 · 0 0

20. ionic === sodium chloride === NaCl (complete electron transfer in bond formation)
covalent === water === H2O (electron sharing in bond formation)

36. hexane and hexone.

Paper chromatography is a method to separate a mixture of compounds on the basis of solubility on a stationary and transfer phase.

43. Methane. CH4. The carbon has eight electrons surrounding it.

2007-05-16 16:32:56 · answer #3 · answered by Anonymous · 0 0

20. MgSO4
Mg and S-ionic bond
S and O- covalent bond
Magnesium sulfate

36. component of ink(a ballpen ink)
Chromatography is the seperation of compound into their chemical components due to their difference in solubility.
43. SiCl4- silicon tetrachlorate

50. HCl + NaHCO3==> NaCl + H2O + CO2

n(HCl)= 10.0g/35.5g/mol=0.282mol
n(HCl)=n(NaHCO3)
n(NaHCO3)= 0.282mol
mass(NaHCO3)=mol x MM
mass(NaHCO3)= 0.282mol x84.0g/mol=23.7g

%yield= actual g NaHCO3/ theoretical g NaHCO3
75%= x/23.7g
x=17.775g~ 17.8g

2007-05-16 16:29:40 · answer #4 · answered by Anonymous · 0 0

This is a neat assignment. Look critically at each of the clues to identify what they mean, then think of an example. For example #18: A density less than 1.0 g/mL means that it is lighter than water. There are numerous possibilities. Cork floats on water. Diethyl ether is lighter than water. #17: Having a pH greater than 7 means that the substance is basic. So possible answers are lye and many other cleaning chemicals; bases you have worked with in lab such as sodium hydroxide (NaOH).

2016-05-20 16:19:41 · answer #5 · answered by Anonymous · 0 0

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