Oxidation-reduction titration?

Question

we prepare a solution of oxalic acid. we weigh 0.968g H2C2O4 x 2H2O and dissolve it in DI water using a 50.0 mL volumetric flask
1) What is the molarity of this oxalic acid solution?
2) What is the equation for the oxidation of the oxalic acid?
3) What is the normality of this solution?

Answer 1

Atomic weights: H=1 C=12 O=16 H2C2O4=90

Let the solution be called S

0.986gH2C2O4/50mlS x 1molH2C2O4/90gH2C2O4 x 1000mLS/1LS = (0.986)(1000)/(50)(90) = 0.219molH2C2O4/1LS so 0.219M

H2C2O4 ===> 2CO2 + 2e- + 2H+

0.219M/2 = 0.110N