How many milliliters of .45M hydrochloric acid must be added to 25.0 mL of 1.00 M potassium hydroxide to make?

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2007-05-16 15:34:33 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

Moles KOH = 25.0 x 1.00 / 1000 = 0.025

If you need pH = 7

moles HCl = 0.025

M = moles / V

V = moles / M = 0.025 / 0.45 = 0.055 L = 55.5 mL

2007-05-16 15:39:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋

The rule is vol(1) x conc (1) = vol (2) x conc (2)

so Vol (HCl) x 0.45 = 25 x 1.0
so vol HCl = 25/.45 =55.55 ml
to make a neutral solution.

2007-05-16 22:40:23 · answer #2 · answered by Aurium 6 · 0⤊ 0⤋

Make what? Love?

2007-05-16 22:39:11 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋