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How in the hell do you find the common denomenator? It has been so long, I don't remember! LOL Help please?

2007-05-16 06:23:56 · 5 answers · asked by ? 2 in Education & Reference Homework Help

Thank you everyone for your help! It sounds bad but I'm pretty rusty at my fractions anymore! LOL
Thanks again, I really appreciate it.

2007-05-16 11:15:26 · update #1

5 answers

LCD = Lowest Common Denominator. The smallest number evenly divisible by both denominators (ie. no remainders).
Example:

1/3 + 1/4

The lowest common denominator is 12.
1/3 x 4 = 4/12
1/4 x 3 = 3/12

4/12 + 3/12 = 7/12.

2007-05-16 06:33:05 · answer #1 · answered by 2007_Shelby_GT500 7 · 0 0

hi... hope this helps...

for "like terms", the denominator is the common denominator.

for example:
1/5 ; 3/5
the common denominator is 5

for "unlike terms", to obtain the "common denominator" (also known as the "LCD" or "least common denominator"), usually what is done is:

if there are only two terms involved; just multiply the
denominators, then you have the lowest terms:
example: 1/5 & 2/3
denominators : 5 & 3
multiplying : 5 x 3 = 15
therefore : common denominator = 15


if there are more than two terms involved; look for a
number that can be divided by all of the denominators
given, then you have the lowewst term:
example: 3/4 ; 2/3 & 1/2
denominators : 4; 3 & 2
number dibvisible by 4, 3 & 2: 12
therefore : common denominator = 12

remember: 2 terms (fractions) just multiply the denominators
more than 2 terms, look for a number that can be
divided by all of the denominators given

"multiply" or "divide".... :) good luck!

2007-05-16 13:58:37 · answer #2 · answered by rustyandteng 1 · 1 0

Times the 2/3 denominators together

2007-05-16 13:26:34 · answer #3 · answered by Danny G 3 · 0 1

Largest number both bottom numbers can fit in to

ie... 3/4 2/3 5/6 - common denominator is 12

2007-05-16 13:28:58 · answer #4 · answered by fire_music_bk 4 · 1 2

Here's an example for you...

http://en.wikipedia.org/wiki/Least_common_denominator

I'm a Math Tutor...

2007-05-16 13:32:52 · answer #5 · answered by Rmprrmbouncer 5 · 0 0

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