completing the square m^2 = -6m -7?

Question

I need help in underdtanding the easiest way to do this.

Answer 1

m² + 6m + 7 = 0
(m² + 6m + 9) - 9 + 7 = 0
(m + 3)² = 2
(m + 3) = ±√2
m = - 3 ±√2
m = - 3 +√2 , m = - 3 - √2

Answer 2

I'm not sure here you are in math. But unless you are just visiting algebra, this should be so simple for you. Th semester's over soon, and it's kind of late to be introducing something like this.

Completing the square has already been done for you in the
"Quadratic Formula". All you need to do s get the equation to look like
ax² + bx + c = 0

To do that you have to get everything on one side of the equation. Ok, so you don't have an "x" pretend "m" is the "x"

Get "m² = -6m -7" in the form
am² + bm + c = 0 . . . . . . . . . . . . . . . . . . . . . (Equation 1)

When you do that, you can apply the Quadratic Formula
x = (-(b) ±√[(b)² - 4(a)(c)])/2(a), or, in this case
m = (-(b) ±√[(b)² - 4(a)(c)])/2(a) . . . . . . . . . . (Equation 2)

Plug the values of a, b, and c from Equation 1 into Equation 2 and solve. There's some arithmetic involved and the answer isn't one nice integer, but I think you can do it.

Answer 3

(m+3)^2 -2=0

Answer 4

Move all to one side and use quadratic formula