How do you square brackets for example see below?

Question

0.3(20-13) Squared

what would this equal

thanks

Answer 1

First do whatever you can inside the brackets.

0.3 (20-13)^2
0.3 (7)^2
0.3 (49)
14.7

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If you have a variable in the brackets, of course this doesn't work. So, you need to use the FOIL rule.

First Outside Inside Last

(x + y)^2
= (x + y)(x + y)

First: (x)(x) = x^2
Outside: (x)(y) = xy
Inside: (y)(x) = xy
Last: (y)(y) = y^2

so you get...
x^2 + xy + xy + y^2
= x^2 + 2xy + y^2

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Incidentally, FOIL works for your example too... It's just more work:
(20 - 13)^2
= (20 - 13)(20 - 13)
= (20)(20) + (20)(-13) + (-13)(20) + (-13)(-13)
= 400 + (-260) + (-260) + 169
= 140 + (-260) + 169
= -120 + 169
= 49

Which is the same as if you worked inside first:
(20 - 13)^2
= (7)^2
= 49

Answer 2

Is it {0.3(20-13)}^2 or 0.3(20-13)^2
In the first case,the solution is
(0.3*7)^2=(2.1)^2=4.41
In the second case the solution is
0.3*7^2
=0.3*49=14.7

Answer 3

the proper method is to use carrots whenever expressing powers:

0.3(20-13)^2=14.7

Therefore you calculate inside parenthesis always first =7.
Then you calculate powers next: 7^2=49.
Then do multiplication/divisions next: 0.3*49=14.7

Always remember your "order of operations." Here's a quick link that shows you them:

http://www.calvin.edu/~rbobeldy/tutorials/excel/form2.htm

Answer 4

first do the subtraction to get 7
then square the 7 to get 49
then multiply 49 by 0.3 to get 14.7

Answer 5

0.3 x 7² = 0.3 x 49 = 14.7

Answer 6

Remember PEMDAS

parenthesis, exponents, multiply, divide, add subtract

first do what is in the parenthesis

20 - 13 = 7

square it = 49

then multiply by .3

you will get 14.7

Answer 7

.3(20-13)^2=
.3(7)^2=
.3(49)=14.7

Answer 8

the result is 14.7 if you calculate properly. good luck.