solve the following system of equations?

Question

2x-3y= -13 at the bottom will be
y=2x-1

Answer 1

In this case, you are already given y in terms of x with the second eqation. So, substitute into the first equation:

2x-3(2x-1) = -13 or
2x-6x+3 = -13 or
-4x+3=-13

Add 4x to both sides and you get

3=-13+4x

Add 13 to both sides and you get

16=4x

Now, divide by 4 on both sides, and you get x=4

Now, substitute that back into one of the equations, say the second, and you get:

y=2(4)-1 or
y=8-1 or
y=7

Answer 2

2x - 3y = -13 ---- (1)
y = 2x - 1 -------- (2)

Plug (2) into (1),
2x - 3(2x - 1) = -13
2x - 6x + 3 = -13
2x - 6x = -16
-4x = -16
x = 4

Plug x = 4 into (2),
y = 2x - 1 = 2(4) - 1 = 7

Answer 3

2x - 3.(2x - 1) = - 13
2x - 6x + 3 = - 13
- 4x = - 16
4x = 16
x = 4

y = 2x - 1
y = 7

x = 4, y = 7

Answer 4

let me try...

2x-3y= -13
y=2x-1

-13+y=4x-3y-1
-13+2x-1=4x-3(2x-1)-1
-13+2x-1=4x-6x-3-1
-14+2x= -2x-4
2x= -2x+10
4x=10

x=2.5
y=4

thx! hope you'll understand!
(i dont believe you cant do it, i am only p6)

Answer 5

2x-3(2x-1)=-13
2x-6x+3=-13
2x-6x=-10
-4x=-10
x=2.5