A. NaC1O3>NaC1+O2
B. MnC12+A1>Mn+A1C13
C. C4H10+O2>H2O+CO2
2007-05-16 02:30:36 · 4 answers · asked by HMMMMM 1 in Science & Mathematics ➔ Physics
For A, its 2NaClO3>2NaCl + 3O2
B. 3MnCl2 + 2Al> 3Mn + 2AlCl3
C. 2C4H10 + 13O2 > 10H2O+ 8CO2
2007-05-16 02:44:07 · answer #1 · answered by Essel T 2 · 0⤊ 0⤋
A. 2NaC1O3 -> 2NaC1 + 3O2
B. 3MnC12 + 2A1 -> 3Mn + 2A1C13
C. C4H10 + 4O2 > 5H2O + 4CO2
This balances the number of atoms on the left = number of atoms on the right for each element. However, I didn't do any RedOx balancing, i.e., number of electrons emitted must = number of electrons absorbed on both sides. But by a cursory look they seem fine.
2007-05-16 14:07:40 · answer #2 · answered by SteadyUnderFire 2 · 0⤊ 0⤋
Talk to the chemists. They specialize in this kind of thing.
2007-05-16 09:44:05 · answer #3 · answered by msi_cord 7 · 0⤊ 1⤋
A. 2NaC1O3 -----> 2NaC1 + 3O2
C. 2C4H10 + 13O2 ------> 10H2O + 8CO2
working on B.
2007-05-16 09:45:30 · answer #4 · answered by Hand In Cup 1 · 0⤊ 0⤋