solve the following system of equations?

Question

x+y=6 and then at the bottom of that will be y=2x

Answer 1

Looking at the second equation, substitute y=2x into the first equation. Thus:

x + (2x) = 6 or 3x = 6

Divide both sides by 3 getting:

x = 2

Plugging into the second equation:

y = 2 (2) or y = 4

to check, plug into the first equation you r values for x and y:

2 + 4 = 6...

Answer 2

In this case, since you are already given that y=2x, then you can directly substitute this into your first equation. So, you get:

x+2x=6 or
3x=6

Now, divide by 3 on both sides, and you get

x=2

Now, substitute that back into either equation (say the second), and you get:

y=2*2 or y=4

Answer 3

x + y = 6 (Eq. 1)
y = 2x (Eq. 2)

Just substitute Eq. 2 into Eq. 1

x + y = 6

Since y = 2x

x + 2x = 6
3x = 6
3x/3 = 6/3
x = 2 ==> value of x

Substitute value of x into Eq. 2
y = 2x
y =2 (2)
y = 4 ===> value of y

To check, substitute the value of x = 2 and y = 4 into Eq. 1

x + y = 6
2 + 4 = 6
6 = 6

Answer 4

Since you already have one equation solved for y, namely, y=2x, substitute 2x in for y in the first equation, giving you:

x+(2x)=6.

Solve for x.

3x=6
x=2

Now, substitute 2 in for x in the first or second equation to solve for y. Both will yield the same result:

(2)+y=6
y=4

y=2(2)
y=4.

So your final solution is (2,4).

Answer 5

x + 2x = 6
3x = 6
x = 2
y = 4

Answer 6

x + 2x = 6
x = 2
y = 4

Answer 7

x + y = 6 ---- (1)
y = 2x -------- (2)

Plug (2) into (1),

x + (2x) = 6
3x = 6
x = 2

Plug x = 2 into (2)

y = 2(2) = 4

Answer 8

y=2x
x+2x=6
x=2
y=4

Answer 9

x+y=6
y=2x

x+2x=6
3x=6

x=2
y=4

Answer 10

x+y=6
y=2x

x+2x=6
3x=6

x=2
y=4