Also, where could I get a list of those combinations?
2007-05-15 20:29:37 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
10*10*10 = 1000
2007-05-15 20:32:15 · answer #1 · answered by michael_scoffield 3 · 0⤊ 0⤋
Since each digit can take a value from 0 to 9 (that means ten different combinations), and since there are three digits, we have a total of 1000 combinations. As already given by the other answerers, we have 000, 001, 002 et. all the way to 999. A full thousand of them.
2007-05-15 20:45:37 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
The 1st digit has 9 possibilities (1 - 9) The 2nd digit has 10 possibilities (0 - 9) The 3rd digit has 10 possibilities (0 - 9) Multiply those possibilities to get 900.
2016-05-19 18:20:20 · answer #3 · answered by ? 4 · 0⤊ 0⤋
it's 9!/3!6!(the rest of 9-3) that means 1*2*3*4*5*6*7*8*9/1*2*3* 1*2*3*4*5*6
<=>362880/4320<=>84 combinations. You can check out the method here http://en.wikipedia.org/wiki/Factorial
this all if we speak with the natural numbers 0,1,2,3,4,5,6,7,8,9
if not you must definate from which number you want (0,0.......1) or else there isn't an answer according to the mathematical theory then there are n combinations :-) i hope i helped you
2007-05-15 21:01:55 · answer #4 · answered by slammingr 2 · 0⤊ 0⤋
Micheal's right, and as to here you can get it a list, its all the integers from
000 to 999
2007-05-15 20:33:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋